What is expand-1/(s(s+1)(s^2-4)) ?

The solution to expand-1/(s(s+1)(s^2-4)) is -1/(s^4-4s^2+s^3-4s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-1/(s(s+1)(s^2-4))

expand

- \frac{1}{s ( s + 1 ) ( s ^{2} - 4 )}

- \frac{1}{s ^{4} - 4 s ^{2} + s ^{3} - 4 s}

Solution steps

- \frac{1}{s ( s + 1 ) ( s ^{2} - 4 )}

Expand

s (s + 1) (s^{2} - 4) : s^{4} - 4 s^{2} + s^{3} - 4 s

= - \frac{1}{s ^{4} + s ^{3} - 4 s ^{2} - 4 s}

\frac{d}{d x} ((y^{2}) (5 sin (x) + 5 cos (x)))

(s^{2} + 4) \cdot (s^{2} + \frac{4}{3})

(- 3 x + 2 + 1)^{2}

\frac{( - y + 4 ) ^{3}}{24}

(\frac{5}{3 x} + \frac{5}{x} = 1) 3 x

What is expand-1/(s(s+1)(s^2-4)) ?
The solution to expand-1/(s(s+1)(s^2-4)) is -1/(s^4-4s^2+s^3-4s)