What is expand ((3+p)^2)/9 ?

The solution to expand ((3+p)^2)/9 is (p^2)/9+(2p)/3+1

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expand ((3+p)^2)/9

expand

\frac{( 3 + p ) ^{2}}{9}

\frac{p ^{2}}{9} + \frac{2 p}{3} + 1

Solution steps

\frac{( 3 + p ) ^{2}}{9}

(3 + p)^{2} = 9 + 6 p + p^{2}

= \frac{9 + 6 p + p ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 + 6 p + p ^{2}}{9} = \frac{9}{9} + \frac{6 p}{9} + \frac{p ^{2}}{9}

= \frac{9}{9} + \frac{6 p}{9} + \frac{p ^{2}}{9}

Apply rule

\frac{a}{a} = 1

\frac{9}{9} = 1

= 1 + \frac{6 p}{9} + \frac{p ^{2}}{9}

Cancel

\frac{6 p}{9} : \frac{2 p}{3}

= 1 + \frac{2 p}{3} + \frac{p ^{2}}{9}

Rewrite in standard form

= \frac{p ^{2}}{9} + \frac{2 p}{3} + 1

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What is expand ((3+p)^2)/9 ?
The solution to expand ((3+p)^2)/9 is (p^2)/9+(2p)/3+1