What is expand (1+2cos(t))*(2sin(t)) ?

The solution to expand (1+2cos(t))*(2sin(t)) is 2sin(t)+4cos(t)sin(t)

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expand (1+2cos(t))*(2sin(t))

expand

(1 + 2 cos (t)) \cdot (2 sin (t))

2 sin (t) + 4 cos (t) sin (t)

Solution steps

(1 + 2 cos (t)) (2 sin (t))

= (2 sin (t)) (1 + 2 cos (t))

Apply the distributive law:

a (b + c) = ab + a c

(2 sin (t)) (1 + 2 cos (t)) = 2 sin (t) \cdot 1 + 2 sin (t) \cdot 2 cos (t)

= 2 sin (t) \cdot 1 + 2 sin (t) \cdot 2 cos (t)

Simplify

2 sin (t) \cdot 1 + 2 sin (t) \cdot 2 cos (t) : 2 sin (t) + 4 cos (t) sin (t)

= 2 sin (t) + 4 cos (t) sin (t)

((x^{2} + y^{2})^{\frac{1}{2}} + 3 y)^{2}

(4 x^{2} + 3 cos (y)) d x - x sin (y) d y

- 10 x^{\frac{2}{3}} (4 x^{4} - 4 x^{2} + 5)

\frac{( x ^{2} - b ) \cdot y \cdot tan ( 7 )}{cos ( x ^{2} ) \cdot π r}

\frac{16 a ^{2} + 12 ab + 9 b ^{3}}{2 ( 16 a ^{2} + 12 ab + 9 b ^{2} )}

What is expand (1+2cos(t))*(2sin(t)) ?
The solution to expand (1+2cos(t))*(2sin(t)) is 2sin(t)+4cos(t)sin(t)