What is expand (4s+1)/(s(2s+1)(s+1)) ?

The solution to expand (4s+1)/(s(2s+1)(s+1)) is (4s+1)/(2s^3+3s^2+s)

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expand (4s+1)/(s(2s+1)(s+1))

expand

\frac{4 s + 1}{s ( 2 s + 1 ) ( s + 1 )}

\frac{4 s + 1}{2 s ^{3} + 3 s ^{2} + s}

Solution steps

\frac{4 s + 1}{s ( 2 s + 1 ) ( s + 1 )}

Expand

s (2 s + 1) (s + 1) : 2 s^{3} + 3 s^{2} + s

= \frac{4 s + 1}{2 s ^{3} + 3 s ^{2} + s}

\frac{( x - 0 ) ( x - 1 ) ( x - 4 )}{- 4}

(\frac{1}{x ^{2}} + y^{3})^{4}

(1 + 2 x^{3}) e^{x^{2}}

- 9 (5 + 3 h - 4 i)

(x - \frac{2}{x})^{15}

What is expand (4s+1)/(s(2s+1)(s+1)) ?
The solution to expand (4s+1)/(s(2s+1)(s+1)) is (4s+1)/(2s^3+3s^2+s)