What is expand ((x-0)(x-1)(x-4))/(-4) ?

The solution to expand ((x-0)(x-1)(x-4))/(-4) is -(x^3)/4+(5x^2)/4-x

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expand ((x-0)(x-1)(x-4))/(-4)

expand

\frac{( x - 0 ) ( x - 1 ) ( x - 4 )}{- 4}

- \frac{x ^{3}}{4} + \frac{5 x ^{2}}{4} - x

Solution steps

\frac{( x - 0 ) ( x - 1 ) ( x - 4 )}{- 4}

x - 0 = x

= \frac{x ( x - 1 ) ( x - 4 )}{- 4}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{x ( x - 1 ) ( x - 4 )}{4}

Expand

x (x - 1) (x - 4) : x^{3} - 5 x^{2} + 4 x

= - \frac{x ^{3} - 5 x ^{2} + 4 x}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 5 x ^{2} + 4 x}{4} = - (\frac{x ^{3}}{4}) - (- \frac{5 x ^{2}}{4}) - (\frac{4 x}{4})

= - (\frac{x ^{3}}{4}) - (- \frac{5 x ^{2}}{4}) - (\frac{4 x}{4})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{3}}{4} + \frac{5 x ^{2}}{4} - \frac{4 x}{4}

Divide the numbers:

\frac{4}{4} = 1

= - \frac{x ^{3}}{4} + \frac{5 x ^{2}}{4} - x

(\frac{1}{x ^{2}} + y^{3})^{4}

(1 + 2 x^{3}) e^{x^{2}}

- 9 (5 + 3 h - 4 i)

(x - \frac{2}{x})^{15}

l im x \Rightarrow 1 (x^{3} + 3 x^{2} - x - 3) (x^{2} - 1)

What is expand ((x-0)(x-1)(x-4))/(-4) ?
The solution to expand ((x-0)(x-1)(x-4))/(-4) is -(x^3)/4+(5x^2)/4-x