What is the d/(d{x)}(({z}(x,y))({x}+{y})) ?

The d/(d{x)}(({z}(x,y))({x}+{y})) is {z}(x,y)(1+d/(d{x)}({y}))

What is the first d/(d{x)}(({z}(x,y))({x}+{y})) ?

The first d/(d{x)}(({z}(x,y))({x}+{y})) is {z}(x,y)(1+d/(d{x)}({y}))

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\frac{d}{d x} ((z (x, y)) (x + y))

z (x, y) (1 + \frac{d}{d x} (y))

Solution steps

\frac{d}{d x} ((z (x, y)) (x + y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z (x, y) \frac{d}{d x} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (x, y) (\frac{d}{d x} (x) + \frac{d}{d x} (y))

\frac{d}{d x} (x) = 1

= z (x, y) (1 + \frac{d}{d x} (y))

\frac{4 x ^{2} + 36 x - 28}{4 x}

\frac{2 n ( - 1 ) ^{n + 1} + 3 ( - 1 ) ^{n + 1} - 1}{4}

tan^{2} (x) + (3 - 1) tan (x) - 3

(2 + 6 y^{3})^{2}

y (6 - x - 3 y)^{2}

What is the d/(d{x)}(({z}(x,y))({x}+{y})) ?
The d/(d{x)}(({z}(x,y))({x}+{y})) is {z}(x,y)(1+d/(d{x)}({y}))
What is the first d/(d{x)}(({z}(x,y))({x}+{y})) ?
The first d/(d{x)}(({z}(x,y))({x}+{y})) is {z}(x,y)(1+d/(d{x)}({y}))