What is expand (4x^2+36x-28)/(4x) ?

The solution to expand (4x^2+36x-28)/(4x) is x+9-7/x

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expand (4x^2+36x-28)/(4x)

expand

\frac{4 x ^{2} + 36 x - 28}{4 x}

x + 9 - \frac{7}{x}

Solution steps

\frac{4 x ^{2} + 36 x - 28}{4 x}

Factor

4 x^{2} + 36 x - 28 : 4 (x^{2} + 9 x - 7)

= \frac{4 ( x ^{2} + 9 x - 7 )}{4 x}

Divide the numbers:

\frac{4}{4} = 1

= \frac{x ^{2} + 9 x - 7}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 9 x - 7}{x} = \frac{x ^{2}}{x} + \frac{9 x}{x} - \frac{7}{x}

= \frac{x ^{2}}{x} + \frac{9 x}{x} - \frac{7}{x}

Cancel

\frac{x ^{2}}{x} : x

= x + \frac{9 x}{x} - \frac{7}{x}

Cancel

\frac{9 x}{x} : 9

= x + 9 - \frac{7}{x}

\frac{2 n ( - 1 ) ^{n + 1} + 3 ( - 1 ) ^{n + 1} - 1}{4}

tan^{2} (x) + (3 - 1) tan (x) - 3

(2 + 6 y^{3})^{2}

y (6 - x - 3 y)^{2}

- \frac{3}{( s ) ( s - 4 ) ( s - 1 )}

What is expand (4x^2+36x-28)/(4x) ?
The solution to expand (4x^2+36x-28)/(4x) is x+9-7/x