What is expand-3/((s)(s-4)(s-1)) ?

The solution to expand-3/((s)(s-4)(s-1)) is -3/(s^3-5s^2+4s)

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expand-3/((s)(s-4)(s-1))

expand

- \frac{3}{( s ) ( s - 4 ) ( s - 1 )}

- \frac{3}{s ^{3} - 5 s ^{2} + 4 s}

Solution steps

- \frac{3}{( s ) ( s - 4 ) ( s - 1 )}

Remove parentheses:

(a) = a

= - \frac{3}{s ( s - 4 ) ( s - 1 )}

Expand

s (s - 4) (s - 1) : s^{3} - 5 s^{2} + 4 s

= - \frac{3}{s ^{3} - 5 s ^{2} + 4 s}

(x + 1) \cdot (2 x^{2} + 1)

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\frac{\partial}{\partial x} ((z) (7 x yz - e^{z}))

(16 + tan (x)) (16 - tan (x)) + sec^{2} (x)

\frac{( x - 2 ) ( x - 3 )}{2}

What is expand-3/((s)(s-4)(s-1)) ?
The solution to expand-3/((s)(s-4)(s-1)) is -3/(s^3-5s^2+4s)