What is expand (x-(5x-1)/3 =4x-3/5)15 ?

The solution to expand (x-(5x-1)/3 =4x-3/5)15 is -10x+5=4x-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-(5x-1)/3 =4x-3/5)15

expand

(x - \frac{5 x - 1}{3} = 4 x - \frac{3}{5}) 15

- 10 x + 5 = 4 x - 9

Solution steps

(x - \frac{5 x - 1}{3} = 4 x - \frac{3}{5}) \cdot 15

= 15 (x - 4 = \frac{5 x - 1}{3} x - \frac{3}{5})

Distribute parentheses

= 15 x + 15 (- \frac{5 x - 1}{3} = 4 x) + 15 (- \frac{3}{5})

Apply minus-plus rules

+ (- a) = - a

15 x - 15 \cdot \frac{5 x - 1}{3} = 4 x - 15 \cdot \frac{3}{5}

Simplify

15 x - 15 \cdot \frac{5 x - 1}{3} = 4 x - 15 \cdot \frac{3}{5} : - 10 x + 5 = 4 x - 9

- 10 x + 5 = 4 x - 9

- 3 (x - \frac{1}{8})

- \frac{16 ( 2 x ^{2} + 1 )}{x + 2}

(x^{2} + 4)^{3} ln (3 x)

- 3 (2 - 4) + 9 (2)^{'}

2 \cdot (2 + \frac{2}{11})

What is expand (x-(5x-1)/3 =4x-3/5)15 ?
The solution to expand (x-(5x-1)/3 =4x-3/5)15 is -10x+5=4x-9