What is expand (2x^5+4x^3-3x^2+3x-1)/((x^3+1)^3) ?

The solution to expand (2x^5+4x^3-3x^2+3x-1)/((x^3+1)^3) is (2x^5+4x^3-3x^2+3x-1)/(x^9+3x^6+3x^3+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^5+4x^3-3x^2+3x-1)/((x^3+1)^3)

expand

\frac{2 x ^{5} + 4 x ^{3} - 3 x ^{2} + 3 x - 1}{( x ^{3} + 1 ) ^{3}}

\frac{2 x ^{5} + 4 x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{9} + 3 x ^{6} + 3 x ^{3} + 1}

Solution steps

\frac{2 x ^{5} + 4 x ^{3} - 3 x ^{2} + 3 x - 1}{( x ^{3} + 1 ) ^{3}}

(x^{3} + 1)^{3} = x^{9} + 3 x^{6} + 3 x^{3} + 1

= \frac{2 x ^{5} + 4 x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{9} + 3 x ^{6} + 3 x ^{3} + 1}

\frac{1}{( x ^{2} - x + 1 ) ( x ^{2} - x + 2 )}

\frac{1}{( s + 10 ) ( s + 2 ) ^{2}}

4 (8 e + 28)

\frac{1}{( x - 3 ) ( x + 3 )}

(3 + M i)^{2}

What is expand (2x^5+4x^3-3x^2+3x-1)/((x^3+1)^3) ?
The solution to expand (2x^5+4x^3-3x^2+3x-1)/((x^3+1)^3) is (2x^5+4x^3-3x^2+3x-1)/(x^9+3x^6+3x^3+1)