What is expand (7+4/(1+i)-2i)(7+4/(1+i)-2i) ?

The solution to expand (7+4/(1+i)-2i)(7+4/(1+i)-2i) is 65-72i

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expand (7+4/(1+i)-2i)(7+4/(1+i)-2i)

expand

(7 + \frac{4}{1 + i} - 2 i) (7 + \frac{4}{1 + i} - 2 i)

65 - 72 i

Solution steps

(7 + \frac{4}{1 + i} - 2 i) (7 + \frac{4}{1 + i} - 2 i)

Distribute parentheses

= 7 \cdot 7 + 7 \cdot \frac{4}{1 + i} + 7 (- 2 i) + \frac{4}{1 + i} \cdot 7 + \frac{4}{1 + i} \cdot \frac{4}{1 + i} + \frac{4}{1 + i} (- 2 i) - 2 i 7 - 2 i \frac{4}{1 + i} - 2 i (- 2 i)

Simplify

7 \cdot 7 + 7 \cdot \frac{4}{1 + i} + 7 (- 2 i) + \frac{4}{1 + i} \cdot 7 + \frac{4}{1 + i} \cdot \frac{4}{1 + i} + \frac{4}{1 + i} (- 2 i) - 2 i 7 - 2 i \frac{4}{1 + i} - 2 i (- 2 i) : - 72 i + 65

= - 72 i + 65

Rewrite in standard complex form:

65 - 72 i

= 65 - 72 i

(x + 3 + 4)^{2}

cot (x) \cdot (tan (x) + sec (x))

(\frac{2}{3} (x - 3))^{2} + 4

(5 x - 3) (4 + \frac{3}{x ^{2}})

(- 0.5 + 0.5 i)^{5}

What is expand (7+4/(1+i)-2i)(7+4/(1+i)-2i) ?
The solution to expand (7+4/(1+i)-2i)(7+4/(1+i)-2i) is 65-72i