What is expand (f(x)=-3x+3/5)(x) ?

The solution to expand (f(x)=-3x+3/5)(x) is xf(x)=-3x^2+(3x)/5

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expand (f(x)=-3x+3/5)(x)

expand

(f (x) = - 3 x + \frac{3}{5}) (x)

x f (x) = - 3 x^{2} + \frac{3 x}{5}

Solution steps

(f (x) = - 3 x + \frac{3}{5}) (x)

= (x) (= f (x) - 3 x + \frac{3}{5})

Distribute parentheses

(x) f (x) = (x) (- 3 x) + (x) \frac{3}{5}

Apply minus-plus rules

+ (- a) = - a

(x) f (x) = - 3 (x) x + \frac{3}{5} (x)

Simplify

(x) f (x) = - 3 (x) x + \frac{3}{5} (x) : x f (x) = - 3 x^{2} + \frac{3 x}{5}

x f (x) = - 3 x^{2} + \frac{3 x}{5}

\frac{1}{x ^{2} ( x ^{2} + y ^{2} )}

\frac{( x ^{2} + x )}{( x - 4 ) ( x ^{2} + 9 )}

2 (25 + 7)

\frac{1}{( s - 1 ) ( s - 2 ) ( s + 6 )}

- 2 \cdot (2 + 2 - 2)

What is expand (f(x)=-3x+3/5)(x) ?
The solution to expand (f(x)=-3x+3/5)(x) is xf(x)=-3x^2+(3x)/5