What is (x+sqrt(x+4))^2 ?

The solution to (x+sqrt(x+4))^2 is x^2+2xsqrt(x+4)+x+4

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simplify (x+sqrt(x+4))^2

simplify

(x + x + 4)^{2}

x^{2} + 2 x x + 4 + x + 4

Solution steps

(x + x + 4)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(x + x + 4)^{2} = x^{2} + 2 x x + 4 + (x + 4)^{2}

= x^{2} + 2 x x + 4 + (x + 4)^{2}

Apply exponent rule:

assuming

n i s o dd or a \geq 0

(x + 4)^{2} = x + 4

= x^{2} + 2 x x + 4 + x + 4

\frac{( s ( s + 5 ) ( s + 6 ) ( s ^{2} + 2 s + 2 ) )}{s + 3}

(\frac{226}{2} + 2) (\frac{226}{2} - 2) (11)

(\frac{1}{2} m - n)^{3}

(x + y) y d x + (2 y + x - 1) d y

(x^{\frac{1}{3}} - 1)^{2}

What is (x+sqrt(x+4))^2 ?
The solution to (x+sqrt(x+4))^2 is x^2+2xsqrt(x+4)+x+4