What is (\partial)/(\partial x)((y)(7xy+4)^2) ?

The answer to (\partial)/(\partial x)((y)(7xy+4)^2) is 14y^2(7yx+4)

Popular >

(\partial)/(\partial x)((y)(7xy+4)^2)

\frac{\partial}{\partial x} ((y) (7 x y + 4)^{2})

14 y^{2} (7 y x + 4)

Solution steps

\frac{\partial}{\partial x} ((y) (7 x y + 4)^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} ((7 x y + 4)^{2})

Apply the chain rule:

2 (7 x y + 4) \frac{\partial}{\partial x} (7 x y + 4)

= 2 (7 x y + 4) \frac{\partial}{\partial x} (7 x y + 4)

\frac{\partial}{\partial x} (7 x y + 4) = 7 y

= y \cdot 2 (7 x y + 4) \cdot 7 y

Simplify

y \cdot 2 (7 x y + 4) \cdot 7 y : 14 y^{2} (7 y x + 4)

= 14 y^{2} (7 y x + 4)

[\frac{( w ^{2} - 3 ) ( 4 w + 2 )}{w + 1}]^{^{'}}

\frac{2 x}{( x ^{2} - 4 ) ^{2}}

(a - λ) (b - λ) (c - λ) (d - λ) (e - λ)

(sin (θ) - 2 r cos^{2} (θ)) d r + r cos (θ) (2 r sin (θ) + 1) d θ

\frac{z ^{2} - 6 z + 8}{( z + 1 ) ( z + 2 )}

What is (\partial)/(\partial x)((y)(7xy+4)^2) ?
The answer to (\partial)/(\partial x)((y)(7xy+4)^2) is 14y^2(7yx+4)