What is expand (2x-5)x^{2/3} ?

The solution to expand (2x-5)x^{2/3} is 2x^{5/3}-x^{2/3}*5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x-5)x^{2/3}

expand

(2 x - 5) x^{\frac{2}{3}}

2 x^{\frac{5}{3}} - x^{\frac{2}{3}} \cdot 5

Solution steps

(2 x - 5) x^{\frac{2}{3}}

= x^{\frac{2}{3}} (2 x - 5)

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{2}{3}} (2 x - 5) = x^{\frac{2}{3}} \cdot 2 x - x^{\frac{2}{3}} \cdot 5

= x^{\frac{2}{3}} \cdot 2 x - x^{\frac{2}{3}} \cdot 5

Simplify

x^{\frac{2}{3}} \cdot 2 x : 2 x^{\frac{5}{3}}

= 2 x^{\frac{5}{3}} - x^{\frac{2}{3}} \cdot 5

(x^{4}) (- \frac{ln ( x )}{4 x ^{3}} - \frac{1}{12 x ^{3}})

(x - \frac{5}{8}) (x + \frac{5}{8})

(x + 3) (x + 3)^{'}

\frac{1}{4} (1 - cos (x))^{2}

1 - cos (x) + ln (2) (1 + tan (22 x)) + 2 arcsin (3 x)

What is expand (2x-5)x^{2/3} ?
The solution to expand (2x-5)x^{2/3} is 2x^{5/3}-x^{2/3}*5