What is expand (t+2)^2+e^{-2t}-2cos(2t) ?

The solution to expand (t+2)^2+e^{-2t}-2cos(2t) is t^2+4t+4+e^{-2t}-2cos(2t)

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expand (t+2)^2+e^{-2t}-2cos(2t)

expand

(t + 2)^{2} + e^{- 2 t} - 2 cos (2 t)

t^{2} + 4 t + 4 + e^{- 2 t} - 2 cos (2 t)

Solution steps

(t + 2)^{2} + e^{- 2 t} - 2 cos (2 t)

(t + 2)^{2} : t^{2} + 4 t + 4

= t^{2} + 4 t + 4 + e^{- 2 t} - 2 cos (2 t)

- \frac{25 ( 4 + x )}{16 ( y - 5 )}

\frac{( a ^{2} + 2 a + 4 ) ( a ^{2} - 2 a + 4 )}{a}

x (2 - ln (x))

\frac{d}{d t} ((x) (4 x + 2 y))

(e + 3) (e - 3)

What is expand (t+2)^2+e^{-2t}-2cos(2t) ?
The solution to expand (t+2)^2+e^{-2t}-2cos(2t) is t^2+4t+4+e^{-2t}-2cos(2t)