What is expand (x+1)e^{2x}dx ?

The solution to expand (x+1)e^{2x}dx is e^{2x}xdx+e^{2x}dx

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expand (x+1)e^{2x}dx

expand

(x + 1) e^{2 x} d x

e^{2 x} x d x + e^{2 x} d x

Solution steps

(x + 1) e^{2 x} d x

= e^{2 x} (x + 1) d x

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 x} d x, b = x, c = 1

= e^{2 x} d xx + e^{2 x} d x \cdot 1

= e^{2 x} x d x + 1 \cdot e^{2 x} d x

Multiply:

1 \cdot e^{2 x} = e^{2 x}

= e^{2 x} x d x + e^{2 x} d x

π x (2 x + 4)^{2}

n 3 (k + m)

\frac{( 2 x - 3 ) ( x + 1 )}{( x - 4 ) ( x + 3 )}

\frac{x ^{2} ( x + 2 )}{2 ( 2 x + 9 ) ( x + 8 )}

f oco (0, - 3)

What is expand (x+1)e^{2x}dx ?
The solution to expand (x+1)e^{2x}dx is e^{2x}xdx+e^{2x}dx