What is expand (1+tan(α)tan(β))tan(α+β) ?

The solution to expand (1+tan(α)tan(β))tan(α+β) is tan(α+β)+tan(α+β)tan(α)tan(β)

Popular >

expand (1+tan(α)tan(β))tan(α+β)

expand

(1 + tan (α) tan (β)) tan (α + β)

tan (α + β) + tan (α + β) tan (α) tan (β)

Solution steps

(1 + tan (α) tan (β)) tan (α + β)

= tan (α + β) (1 + tan (α) tan (β))

Apply the distributive law:

a (b + c) = ab + a c

tan (α + β) (1 + tan (α) tan (β)) = tan (α + β) \cdot 1 + tan (α + β) tan (α) tan (β)

= tan (α + β) \cdot 1 + tan (α + β) tan (α) tan (β)

Apply rule:

a \cdot 1 = a

tan (α + β) \cdot 1 = tan (α + β)

= tan (α + β) + tan (α + β) tan (α) tan (β)

(- x - 3) (- x + 3)

(a + e - b + i) x^{2} + (a + e + b + i) x + (c + o)

(1 - \frac{x}{4})^{\frac{1}{2}}

\frac{4 x - 5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}}

\frac{3 s ^{2} + 2}{3 ( s ^{3} - s ^{2} + 4 s - 4 )}

What is expand (1+tan(α)tan(β))tan(α+β) ?
The solution to expand (1+tan(α)tan(β))tan(α+β) is tan(α+β)+tan(α+β)tan(α)tan(β)