What is expand (d^2y)/(d^2x)(x+xy+y=1) ?

The solution to expand (d^2y)/(d^2x)(x+xy+y=1) is y+y^2+(y^2)/x =1

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expand (d^2y)/(d^2x)(x+xy+y=1)

expand

\frac{d ^{2} y}{d ^{2} x} (x + x y + y = 1)

y + y^{2} + \frac{y ^{2}}{x} = 1

Solution steps

\frac{d ^{2} y}{d ^{2} x} (x + x y + y = 1)

= \frac{d ^{2} y}{d ^{2} x} (x + x y + 1 = y)

Distribute parentheses

\frac{d ^{2} y}{d ^{2} x} x + \frac{d ^{2} y}{d ^{2} x} x y + \frac{d ^{2} y}{d ^{2} x} y = 1

Expand

\frac{d ^{2} y}{d ^{2} x} x + \frac{d ^{2} y}{d ^{2} x} x y + \frac{d ^{2} y}{d ^{2} x} y : y + y^{2} + \frac{y ^{2}}{x}

y + y^{2} + \frac{y ^{2}}{x} = 1

(x + \frac{1}{2}) (x - 1)

\frac{e ^{2 s}}{( s + 4 ) ( s + 3 )}

(3 + 1) + (3 - 1) i

((- 1 + \frac{4 a}{n})^{2} - 2 (- 1 + \frac{4 a}{n})) \frac{4}{n}

(2 x - y) d x - (x + 4) d y

What is expand (d^2y)/(d^2x)(x+xy+y=1) ?
The solution to expand (d^2y)/(d^2x)(x+xy+y=1) is y+y^2+(y^2)/x =1