What is expand ((-1+(4a)/n)^2-2(-1+(4a)/n)) 4/n ?

The solution to expand ((-1+(4a)/n)^2-2(-1+(4a)/n)) 4/n is (4(-n+4a)^2)/(n^3)-(8(-n+4a))/(n^2)

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expand ((-1+(4a)/n)^2-2(-1+(4a)/n)) 4/n

expand

((- 1 + \frac{4 a}{n})^{2} - 2 (- 1 + \frac{4 a}{n})) \frac{4}{n}

\frac{4 ( - n + 4 a ) ^{2}}{n ^{3}} - \frac{8 ( - n + 4 a )}{n ^{2}}

Solution steps

((- 1 + \frac{4 a}{n})^{2} - 2 (- 1 + \frac{4 a}{n})) \frac{4}{n}

= \frac{4}{n} ((- 1 + \frac{4 a}{n})^{2} - 2 (- 1 + \frac{4 a}{n}))

Apply the distributive law:

a (b - c) = ab - a c

\frac{4}{n} ((- 1 + \frac{4 a}{n})^{2} - 2 (- 1 + \frac{4 a}{n})) = \frac{4}{n} (- 1 + \frac{4 a}{n})^{2} - \frac{4}{n} \cdot 2 (- 1 + \frac{4 a}{n})

= \frac{4}{n} (- 1 + \frac{4 a}{n})^{2} - \frac{4}{n} \cdot 2 (- 1 + \frac{4 a}{n})

Simplify

\frac{4}{n} (- 1 + \frac{4 a}{n})^{2} - \frac{4}{n} \cdot 2 (- 1 + \frac{4 a}{n}) : \frac{4 ( - n + 4 a ) ^{2}}{n ^{3}} - \frac{8 ( - n + 4 a )}{n ^{2}}

= \frac{4 ( - n + 4 a ) ^{2}}{n ^{3}} - \frac{8 ( - n + 4 a )}{n ^{2}}

(2 x - y) d x - (x + 4) d y

(- 3 e^{- t}) (- 5 e^{4 t} + e^{- 2 t})

\frac{2 x - 1}{( x - 3 ) ( x + 2 )}

2^{3}

What is expand ((-1+(4a)/n)^2-2(-1+(4a)/n)) 4/n ?
The solution to expand ((-1+(4a)/n)^2-2(-1+(4a)/n)) 4/n is (4(-n+4a)^2)/(n^3)-(8(-n+4a))/(n^2)