What is expand (t(-27te^{-t}-11t-8))/3 ?

The solution to expand (t(-27te^{-t}-11t-8))/3 is -9e^{-t}t^2-(11t^2)/3-(8t)/3

Popular >

expand (t(-27te^{-t}-11t-8))/3

expand

\frac{t ( - 27 t e ^{- t} - 11 t - 8 )}{3}

- 9 e^{- t} t^{2} - \frac{11 t ^{2}}{3} - \frac{8 t}{3}

Solution steps

\frac{t ( - 27 t e ^{- t} - 11 t - 8 )}{3}

Expand

t (- 27 t e^{- t} - 11 t - 8) : - 27 e^{- t} t^{2} - 11 t^{2} - 8 t

= \frac{- 27 e ^{- t} t ^{2} - 11 t ^{2} - 8 t}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 27 e ^{- t} t ^{2} - 11 t ^{2} - 8 t}{3} = - \frac{27 e ^{- t} t ^{2}}{3} - \frac{11 t ^{2}}{3} - \frac{8 t}{3}

= - \frac{27 e ^{- t} t ^{2}}{3} - \frac{11 t ^{2}}{3} - \frac{8 t}{3}

Divide the numbers:

\frac{27}{3} = 9

= - 9 e^{- t} t^{2} - \frac{11 t ^{2}}{3} - \frac{8 t}{3}

2 (16 + \frac{1}{5} x)^{2} - (20 + \frac{1}{4} x)^{2}

\frac{2 ( x ^{3} - 2 )}{( x - 3 ) ( x ^{2} + 3 x + 9 )}

(3 - sin (x))^{2}

\frac{- 1 - 1 - 4 ( - π - 4 πn )}{2}

(2 t - e^{4 t})^{2}

What is expand (t(-27te^{-t}-11t-8))/3 ?
The solution to expand (t(-27te^{-t}-11t-8))/3 is -9e^{-t}t^2-(11t^2)/3-(8t)/3