What is expand xsqrt(2x-1)(x^2+3)^2 ?

The solution to expand xsqrt(2x-1)(x^2+3)^2 is x^5sqrt(2x-1)+6x^3sqrt(2x-1)+9xsqrt(2x-1)

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expand xsqrt(2x-1)(x^2+3)^2

expand

x 2 x - 1 (x^{2} + 3)^{2}

x^{5} 2 x - 1 + 6 x^{3} 2 x - 1 + 9 x 2 x - 1

Solution steps

x 2 x - 1 (x^{2} + 3)^{2}

= x (x^{2} + 3)^{2} 2 x - 1

Expand

(x^{2} + 3)^{2} : x^{4} + 6 x^{2} + 9

= x (x^{4} + 6 x^{2} + 9) 2 x - 1

= x 2 x - 1 (x^{4} + 6 x^{2} + 9)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

x 2 x - 1 (x^{4} + 6 x^{2} + 9) = x 2 x - 1 x^{4} + x 2 x - 1 \cdot 6 x^{2} + x 2 x - 1 \cdot 9

= x 2 x - 1 x^{4} + x 2 x - 1 \cdot 6 x^{2} + x 2 x - 1 \cdot 9

Simplify

x 2 x - 1 x^{4} + x 2 x - 1 \cdot 6 x^{2} + x 2 x - 1 \cdot 9 : x^{5} 2 x - 1 + 6 x^{3} 2 x - 1 + 9 x 2 x - 1

= x^{5} 2 x - 1 + 6 x^{3} 2 x - 1 + 9 x 2 x - 1

\frac{2500 ( - 104 + 43 3 )}{5787}

\frac{12 x}{( 1 - x ^{2} ) ^{2}}

\frac{5 x ^{2} + 6 x + 9}{( x - 3 ) ^{2} \cdot ( x + 1 ) ^{2}}

\frac{2 n}{( 1 - x ) ^{2}}

(tan (z) - sin (x) sin (y)) d x + cos (x) cos (y) d y

What is expand xsqrt(2x-1)(x^2+3)^2 ?
The solution to expand xsqrt(2x-1)(x^2+3)^2 is x^5sqrt(2x-1)+6x^3sqrt(2x-1)+9xsqrt(2x-1)