What is expand 4cos(t-2)u(t-2) ?

The solution to expand 4cos(t-2)u(t-2) is 4tucos(t-2)-8ucos(t-2)

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expand 4cos(t-2)u(t-2)

expand

4 cos (t - 2) u (t - 2)

4 t u cos (t - 2) - 8 u cos (t - 2)

Solution steps

4 cos (t - 2) u (t - 2)

= 4 u cos (t - 2) (t - 2)

Apply the distributive law:

a (b - c) = ab - a c

4 u cos (t - 2) (t - 2) = 4 u cos (t - 2) t - 4 u cos (t - 2) \cdot 2

= 4 u cos (t - 2) t - 4 u cos (t - 2) \cdot 2

Simplify

4 u cos (t - 2) t - 4 u cos (t - 2) \cdot 2 : 4 t u cos (t - 2) - 8 u cos (t - 2)

= 4 t u cos (t - 2) - 8 u cos (t - 2)

t + z (cos (t)) d t + (sin (t) - 3 z^{2} + 5) d z

lo g_{10} (3) (x + 5)

(u - 1) u

\frac{x ^{2} - 5 x - 9}{( 2 x + 3 ) ( x - 4 )}

(sec (θ) + tan (θ)) (sin (θ) - 1)

What is expand 4cos(t-2)u(t-2) ?
The solution to expand 4cos(t-2)u(t-2) is 4tucos(t-2)-8ucos(t-2)