What is expand e^{2t}(cos(2x)-sin(2x)) ?

The solution to expand e^{2t}(cos(2x)-sin(2x)) is e^{2t}cos(2x)-e^{2t}sin(2x)

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expand e^{2t}(cos(2x)-sin(2x))

expand

e^{2 t} (cos (2 x) - sin (2 x))

e^{2 t} cos (2 x) - e^{2 t} sin (2 x)

Solution steps

e^{2 t} (cos (2 x) - sin (2 x))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 t}, b = cos (2 x), c = sin (2 x)

= e^{2 t} cos (2 x) - e^{2 t} sin (2 x)

2 (2 x^{2} + y^{2}) d x - x y d y

(x + 2 π)^{4}

- (\frac{8 x}{y} - \frac{w}{t})^{2}

(12 x^{(3)} + 6 x^{(2)} - 2 x + 3) d x

What is expand e^{2t}(cos(2x)-sin(2x)) ?
The solution to expand e^{2t}(cos(2x)-sin(2x)) is e^{2t}cos(2x)-e^{2t}sin(2x)