What is expand log_{10}(3)(x^2+1) ?

The solution to expand log_{10}(3)(x^2+1) is log_{10}(3)x^2+log_{10}(3)

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expand log_{10}(3)(x^2+1)

expand

lo g_{10} (3) (x^{2} + 1)

lo g_{10} (3) x^{2} + lo g_{10} (3)

Solution steps

lo g_{10} (3) (x^{2} + 1)

Apply the distributive law:

a (b + c) = ab + a c

lo g_{10} (3) (x^{2} + 1) = lo g_{10} (3) x^{2} + lo g_{10} (3) \cdot 1

= lo g_{10} (3) x^{2} + lo g_{10} (3) \cdot 1

Apply rule:

a \cdot 1 = a

lo g_{10} (3) \cdot 1 = lo g_{10} (3)

= lo g_{10} (3) x^{2} + lo g_{10} (3)

- 6 (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

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l im x \Rightarrow 1 (x^{2} - x) sin (x - 1)

(2 - 1 - x)^{6}

(16 - x^{2}) e^{x^{2}}

What is expand log_{10}(3)(x^2+1) ?
The solution to expand log_{10}(3)(x^2+1) is log_{10}(3)x^2+log_{10}(3)