What is expand ((25x^8-9)^2)/(900x^8) ?

The solution to expand ((25x^8-9)^2)/(900x^8) is (25x^8)/(36)-1/2+9/(100x^8)

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expand ((25x^8-9)^2)/(900x^8)

expand

\frac{( 25 x ^{8} - 9 ) ^{2}}{900 x ^{8}}

\frac{25 x ^{8}}{36} - \frac{1}{2} + \frac{9}{100 x ^{8}}

Solution steps

\frac{( 25 x ^{8} - 9 ) ^{2}}{900 x ^{8}}

(25 x^{8} - 9)^{2} = 625 x^{16} - 450 x^{8} + 81

= \frac{625 x ^{16} - 450 x ^{8} + 81}{900 x ^{8}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{625 x ^{16} - 450 x ^{8} + 81}{900 x ^{8}} = \frac{625 x ^{16}}{900 x ^{8}} - \frac{450 x ^{8}}{900 x ^{8}} + \frac{81}{900 x ^{8}}

= \frac{625 x ^{16}}{900 x ^{8}} - \frac{450 x ^{8}}{900 x ^{8}} + \frac{81}{900 x ^{8}}

Cancel

\frac{625 x ^{16}}{900 x ^{8}} : \frac{25 x ^{8}}{36}

= \frac{25 x ^{8}}{36} - \frac{450 x ^{8}}{900 x ^{8}} + \frac{81}{900 x ^{8}}

Cancel

\frac{450 x ^{8}}{900 x ^{8}} : \frac{1}{2}

= \frac{25 x ^{8}}{36} - \frac{1}{2} + \frac{81}{900 x ^{8}}

Cancel

\frac{81}{900 x ^{8}} : \frac{9}{100 x ^{8}}

= \frac{25 x ^{8}}{36} - \frac{1}{2} + \frac{9}{100 x ^{8}}

(- 1 + i)^{15}

\frac{b}{( s - 5 ) ( s + 5 )}

(\frac{2 t}{5} - \frac{w ^{2}}{4}) (\frac{2 t}{5} + \frac{w ^{2}}{4})

\frac{d}{d θ} ((x (θ)) (3 (1 - cos (θ))))

- \frac{- 5 x + 4}{2 ln ( 5 ) x ( - x + 1 )}

What is expand ((25x^8-9)^2)/(900x^8) ?
The solution to expand ((25x^8-9)^2)/(900x^8) is (25x^8)/(36)-1/2+9/(100x^8)