What is (d^2)/(dx^2)((y)(8-x)) ?

The answer to (d^2)/(dx^2)((y)(8-x)) is 8(d^2y)/(dx^2)-x(d^2y)/(dx^2)-2(dy)/(dx)

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(d^2)/(dx^2)((y)(8-x))

\frac{d ^{2}}{d x ^{2}} ((y) (8 - x))

8 \frac{d ^{2} y}{d x ^{2}} - x \frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x}

Solution steps

\frac{d ^{2}}{d x ^{2}} ((y) (8 - x))

\frac{d}{d x} (y (8 - x)) = \frac{d y}{d x} (8 - x) - y

= \frac{d}{d x} (\frac{d y}{d x} (8 - x) - y)

\frac{d}{d x} (\frac{d y}{d x} (8 - x) - y) = 8 \frac{d ^{2} y}{d x ^{2}} - x \frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x}

= 8 \frac{d ^{2} y}{d x ^{2}} - x \frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x}

0.7 m (1 - e^{- \frac{143.08}{m}})

\frac{4 x ^{2} + 2 x - 1}{x ^{2} ( x + 1 )}

\frac{d ^{2}}{d x ^{2}} ((x^{2} - 3) (2 x^{6} + 3)) + (\frac{2}{e ^{x}})

f (x) (3 x^{2} + 1) (2.4)

\frac{x + 1}{( 2 x - 1 ) ( x - 1 )}

What is (d^2)/(dx^2)((y)(8-x)) ?
The answer to (d^2)/(dx^2)((y)(8-x)) is 8(d^2y)/(dx^2)-x(d^2y)/(dx^2)-2(dy)/(dx)