What is expand 1/(e^s(s^2+1))-2/(se^{2s)(s^2+1)} ?

The solution to expand 1/(e^s(s^2+1))-2/(se^{2s)(s^2+1)} is 1/(e^ss^2+e^s)-2/(e^{2s)s^3+e^{2s}s}

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expand 1/(e^s(s^2+1))-2/(se^{2s)(s^2+1)}

expand

\frac{1}{e ^{s} ( s ^{2} + 1 )} - \frac{2}{s e ^{2 s} ( s ^{2} + 1 )}

\frac{1}{e ^{s} s ^{2} + e ^{s}} - \frac{2}{e ^{2 s} s ^{3} + e ^{2 s} s}

Solution steps

\frac{1}{e ^{s} ( s ^{2} + 1 )} - \frac{2}{s e ^{2 s} ( s ^{2} + 1 )}

Expand

e^{s} (s^{2} + 1) : e^{s} s^{2} + e^{s}

= \frac{1}{e ^{s} s ^{2} + e ^{s}} - \frac{2}{e ^{2 s} s ( s ^{2} + 1 )}

Expand

s e^{2 s} (s^{2} + 1) : e^{2 s} s^{3} + e^{2 s} s

= \frac{1}{e ^{s} s ^{2} + e ^{s}} - \frac{2}{e ^{2 s} s ^{3} + e ^{2 s} s}

\frac{( x - 1 ) ^{2}}{25}

(x - 4) \cdot (x + 4)

(v - 2 (v, a) b - 2 (v, b) b) \cdot (v - 2 (v, a) b - 2 (v, b) b)

(1 - sin (x)) (1 + sin (x))^{'}

\frac{e ^{- 3 s}}{( s - 1 ) ( s ^{2} - s )}

What is expand 1/(e^s(s^2+1))-2/(se^{2s)(s^2+1)} ?
The solution to expand 1/(e^s(s^2+1))-2/(se^{2s)(s^2+1)} is 1/(e^ss^2+e^s)-2/(e^{2s)s^3+e^{2s}s}