What is expand (1-sin(x))(1+sin(x))' ?

The solution to expand (1-sin(x))(1+sin(x))' is (1+sin(x))'-sin(x)(1+sin(x))'

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expand (1-sin(x))(1+sin(x))'

expand

(1 - sin (x)) (1 + sin (x))^{'}

(1 + sin (x))' - sin (x) (1 + sin (x))'

Solution steps

(1 - sin (x)) (1 + sin (x))^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (1 + sin (x))^{'}, b = 1, c = sin (x)

= (1 + sin (x))^{^{'}} 1 - (1 + sin (x))^{^{'}} sin (x)

= 1 (1 + sin (x))^{^{'}} - sin (x) (1 + sin (x))^{^{'}}

Multiply:

1 (1 + sin (x))^{'} = (1 + sin (x))^{'}

= (1 + sin (x))^{^{'}} - sin (x) (1 + sin (x))^{^{'}}

\frac{e ^{- 3 s}}{( s - 1 ) ( s ^{2} - s )}

\frac{1}{s ( 1 + L C s ^{2} )}

(x - 2)^{2} (x - 3 i)^{2}

\frac{lo g _{10} ( 2 )}{lo g _{10} ( 5 b )}

4 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

What is expand (1-sin(x))(1+sin(x))' ?
The solution to expand (1-sin(x))(1+sin(x))' is (1+sin(x))'-sin(x)(1+sin(x))'