What is expand ((2n-1)x^{2(n-1)})/(2n(2n+1)) ?

The solution to expand ((2n-1)x^{2(n-1)})/(2n(2n+1)) is (2nx^{2n-2}-x^{2n-2})/(4n^2+2n)

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expand ((2n-1)x^{2(n-1)})/(2n(2n+1))

expand

\frac{( 2 n - 1 ) x ^{2 (n - 1)}}{2 n ( 2 n + 1 )}

\frac{2 n x ^{2 n - 2} - x ^{2 n - 2}}{4 n ^{2} + 2 n}

Solution steps

\frac{( 2 n - 1 ) x ^{2 (n - 1)}}{2 n ( 2 n + 1 )}

x^{2 (n - 1)} = x^{2 n - 2}

= \frac{x ^{2 n - 2} ( 2 n - 1 )}{2 n ( 2 n + 1 )}

Expand

2 n (2 n + 1) : 4 n^{2} + 2 n

= \frac{x ^{2 n - 2} ( 2 n - 1 )}{4 n ^{2} + 2 n}

Expand

(2 n - 1) x^{2 n - 2} : 2 n x^{2 n - 2} - x^{2 n - 2}

= \frac{2 n x ^{2 n - 2} - x ^{2 n - 2}}{4 n ^{2} + 2 n}

\frac{3 ^{n + 2} - ( - 1 ) ^{n}}{4}

cos (t) h (t - π)

3 - 3 [3 - \frac{( 2 + ( - 5 ) )}{( 3 - 6 )}] - 2 [2 - (- 6)]

- \frac{50 x ^{4}}{( x ^{5} + 5 ) ( x ^{5} - 5 )}

(3, 4) y (- 2, - 3)

What is expand ((2n-1)x^{2(n-1)})/(2n(2n+1)) ?
The solution to expand ((2n-1)x^{2(n-1)})/(2n(2n+1)) is (2nx^{2n-2}-x^{2n-2})/(4n^2+2n)