What is expand ((3x-6)^3)/8 ?

The solution to expand ((3x-6)^3)/8 is (27x^3)/8-(81x^2)/4+(81x)/2-27

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expand ((3x-6)^3)/8

expand

\frac{( 3 x - 6 ) ^{3}}{8}

\frac{27 x ^{3}}{8} - \frac{81 x ^{2}}{4} + \frac{81 x}{2} - 27

Solution steps

\frac{( 3 x - 6 ) ^{3}}{8}

(3 x - 6)^{3} = 27 x^{3} - 162 x^{2} + 324 x - 216

= \frac{27 x ^{3} - 162 x ^{2} + 324 x - 216}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} - 162 x ^{2} + 324 x - 216}{8} = \frac{27 x ^{3}}{8} - \frac{162 x ^{2}}{8} + \frac{324 x}{8} - \frac{216}{8}

= \frac{27 x ^{3}}{8} - \frac{162 x ^{2}}{8} + \frac{324 x}{8} - \frac{216}{8}

Cancel

\frac{162 x ^{2}}{8} : \frac{81 x ^{2}}{4}

= \frac{27 x ^{3}}{8} - \frac{81 x ^{2}}{4} + \frac{324 x}{8} - \frac{216}{8}

Cancel

\frac{324 x}{8} : \frac{81 x}{2}

= \frac{27 x ^{3}}{8} - \frac{81 x ^{2}}{4} + \frac{81 x}{2} - \frac{216}{8}

Divide the numbers:

\frac{216}{8} = 27

= \frac{27 x ^{3}}{8} - \frac{81 x ^{2}}{4} + \frac{81 x}{2} - 27

P (- 7, 2) Q (5, - 3)

(\frac{4}{( n + 1 ) ( n + 2 )})^{\frac{1}{n}}

\frac{i w + a}{( i w + a ) ^{2} + b ^{2}}

2 (\frac{3}{2} x - \frac{1}{2} y)^{2}

\frac{7}{s ( s + 3 ) ( s + 2 )}

What is expand ((3x-6)^3)/8 ?
The solution to expand ((3x-6)^3)/8 is (27x^3)/8-(81x^2)/4+(81x)/2-27