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Popular >

expand (2x+1)y'(x)

Solution

expand

(2 x + 1) y^{'} (x)

Solution

2 x y' (x) + y' (x)

Solution steps

(2 x + 1) y^{'} (x)

Apply the distributive law:

a (b + c) = ab + a c

a = y^{'} (x), b = 2 x, c = 1

= y^{^{'}} (x) 2 x + y^{^{'}} (x) 1

= 2 x y^{^{'}} (x) + 1 y^{^{'}} (x)

Multiply:

1 y^{'} (x) = y^{'} (x)

= 2 x y^{^{'}} (x) + y^{^{'}} (x)

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Frequently Asked Questions (FAQ)

What is expand (2x+1)y'(x) ?
The solution to expand (2x+1)y'(x) is 2xy'(x)+y'(x)