What is expand-2(x+1)sin^2(x+1) ?

The solution to expand-2(x+1)sin^2(x+1) is -2xsin^2(x+1)-2sin^2(x+1)

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expand-2(x+1)sin^2(x+1)

expand

- 2 (x + 1) sin^{2} (x + 1)

- 2 x sin^{2} (x + 1) - 2 sin^{2} (x + 1)

Solution steps

- 2 (x + 1) sin^{2} (x + 1)

= - 2 sin^{2} (x + 1) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

- 2 sin^{2} (x + 1) (x + 1) = - 2 sin^{2} (x + 1) x - 2 sin^{2} (x + 1) \cdot 1

= - 2 sin^{2} (x + 1) x - 2 sin^{2} (x + 1) \cdot 1

Simplify

- 2 sin^{2} (x + 1) x - 2 sin^{2} (x + 1) \cdot 1 : - 2 x sin^{2} (x + 1) - 2 sin^{2} (x + 1)

= - 2 x sin^{2} (x + 1) - 2 sin^{2} (x + 1)

\frac{( x - 5 ) ^{3}}{3}

\frac{n ( 3 n - 1 )}{2}

\frac{x ^{2} + 5 x + 7}{( x ^{2} + 4 x + 5 ) ( s + 1 ) ^{2}}

, (8 x^{2} - 8) + (- 2 x^{2} - 9 x)

\frac{( sin ^{2} ( t ) )}{( 1 - cos ( t ) ) ^{2}}

What is expand-2(x+1)sin^2(x+1) ?
The solution to expand-2(x+1)sin^2(x+1) is -2xsin^2(x+1)-2sin^2(x+1)