What is expand 1/3 \H(t-6)-1/3 e^{-3(t-6)} ?

The solution to expand 1/3 \H(t-6)-1/3 e^{-3(t-6)} is 1/3 \H(t-6)-1/3 e^{-3t+18}

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expand 1/3 \H(t-6)-1/3 e^{-3(t-6)}

expand

\frac{1}{3} H (t - 6) - \frac{1}{3} e^{- 3 (t - 6)}

\frac{1}{3} H (t - 6) - \frac{1}{3} e^{- 3 t + 18}

Solution steps

\frac{1}{3} H (t - 6) - \frac{1}{3} e^{- 3 (t - 6)}

e^{- 3 (t - 6)} = e^{- 3 t + 18}

= \frac{1}{3} H (t - 6) - \frac{1}{3} e^{- 3 t + 18}

\frac{20 ( s + 1 ) ( s + 2 )}{s ^{2} + 32 s + 40}

(x - 4) (x - 6) (x + 7)

\frac{π}{18} (2 sin (7 x) \cdot cos (2 x) - sin (5 x))

\frac{u ^{2} x - u ^{2} x ^{2} - 1}{u ^{4} ( x ^{2} - x ^{3} )}

(t^{2} - x t^{2}) x^{^{'}} + x^{2} + t x^{2}

What is expand 1/3 \H(t-6)-1/3 e^{-3(t-6)} ?
The solution to expand 1/3 \H(t-6)-1/3 e^{-3(t-6)} is 1/3 \H(t-6)-1/3 e^{-3t+18}