What is expand pi/(18)(2sin(7x)*cos(2x)-sin(5x)) ?

The solution to expand pi/(18)(2sin(7x)*cos(2x)-sin(5x)) is pi/9 sin(7x)cos(2x)-pi/(18)sin(5x)

Popular >

expand pi/(18)(2sin(7x)*cos(2x)-sin(5x))

expand

\frac{π}{18} (2 sin (7 x) \cdot cos (2 x) - sin (5 x))

\frac{π}{9} sin (7 x) cos (2 x) - \frac{π}{18} sin (5 x)

Solution steps

\frac{π}{18} (2 sin (7 x) cos (2 x) - sin (5 x))

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{π}{18}, b = 2 sin (7 x) cos (2 x), c = sin (5 x)

= \frac{π}{18} \cdot 2 sin (7 x) cos (2 x) - \frac{π}{18} sin (5 x)

= 2 \cdot \frac{π}{18} sin (7 x) cos (2 x) - \frac{π}{18} sin (5 x)

2 \cdot \frac{π}{18} sin (7 x) cos (2 x) = \frac{π}{9} sin (7 x) cos (2 x)

= \frac{π}{9} sin (7 x) cos (2 x) - \frac{π}{18} sin (5 x)

\frac{u ^{2} x - u ^{2} x ^{2} - 1}{u ^{4} ( x ^{2} - x ^{3} )}

(t^{2} - x t^{2}) x^{^{'}} + x^{2} + t x^{2}

l im x \Rightarrow 5 (x^{2} - 6)

(e^{2 π} - 1) (e^{2 π} + 1)

A (1, - 1) B (- 7, 3)

What is expand pi/(18)(2sin(7x)*cos(2x)-sin(5x)) ?
The solution to expand pi/(18)(2sin(7x)*cos(2x)-sin(5x)) is pi/9 sin(7x)cos(2x)-pi/(18)sin(5x)