What is expand dt((5x^2+2x-8)) ?

The solution to expand dt((5x^2+2x-8)) is 5x^2dt+2xdt-8dt

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expand dt((5x^2+2x-8))

expand

d t ((5 x^{2} + 2 x - 8))

5 x^{2} d t + 2 x d t - 8 d t

Solution steps

d t ((5 x^{2} + 2 x - 8))

Remove parentheses:

(a) = a

= d t (5 x^{2} + 2 x - 8)

Distribute parentheses

= d t \cdot 5 x^{2} + d t \cdot 2 x + d t (- 8)

Apply minus-plus rules

+ (- a) = - a

= 5 x^{2} d t + 2 x d t - 8 d t

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y^{3} - 2^{21}

What is expand dt((5x^2+2x-8)) ?
The solution to expand dt((5x^2+2x-8)) is 5x^2dt+2xdt-8dt