What is expand (1-xe^{xy})e^{xy}y ?

The solution to expand (1-xe^{xy})e^{xy}y is e^{xy}y-e^{2xy}xy

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expand (1-xe^{xy})e^{xy}y

expand

(1 - x e^{x y}) e^{x y} y

e^{x y} y - e^{2 x y} x y

Solution steps

(1 - x e^{x y}) e^{x y} y

= e^{x y} y (1 - e^{x y} x)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x y} y, b = 1, c = x e^{x y}

= e^{x y} y \cdot 1 - e^{x y} y x e^{x y}

= 1 \cdot e^{x y} y - e^{x y} e^{x y} x y

Simplify

1 \cdot e^{x y} y - e^{x y} e^{x y} x y : e^{x y} y - e^{2 x y} x y

= e^{x y} y - e^{2 x y} x y

\frac{d ^{2}}{d x ^{2}} ((y) (12 x - 7 + \frac{8}{x ^{3}}))

(x^{2} + 9 + 6)^{2}

6 (ln (x) + 1)

y^{3} - 2^{21}

\frac{( k + 1 ) ( 3 k + 2 )}{2}

What is expand (1-xe^{xy})e^{xy}y ?
The solution to expand (1-xe^{xy})e^{xy}y is e^{xy}y-e^{2xy}xy