What is expand ((k+1)(3k+2))/2 ?

The solution to expand ((k+1)(3k+2))/2 is (3k^2)/2+(5k)/2+1

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expand ((k+1)(3k+2))/2

expand

\frac{( k + 1 ) ( 3 k + 2 )}{2}

\frac{3 k ^{2}}{2} + \frac{5 k}{2} + 1

Solution steps

\frac{( k + 1 ) ( 3 k + 2 )}{2}

Expand

(k + 1) (3 k + 2) : 3 k^{2} + 5 k + 2

= \frac{3 k ^{2} + 5 k + 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 k ^{2} + 5 k + 2}{2} = \frac{3 k ^{2}}{2} + \frac{5 k}{2} + \frac{2}{2}

= \frac{3 k ^{2}}{2} + \frac{5 k}{2} + \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{3 k ^{2}}{2} + \frac{5 k}{2} + 1

(5 + 7)^{4}

\frac{k ( k + 1 ) ( 2 k + 1 )}{6}

\frac{x - 4 \cdot x + 4}{( x - 2 ) ( x - 4 )}

\frac{6 x ^{2} + 7 x + 9}{3 x}

\frac{( a - x ) ^{4}}{4}

What is expand ((k+1)(3k+2))/2 ?
The solution to expand ((k+1)(3k+2))/2 is (3k^2)/2+(5k)/2+1