What is expand-1/(x(x+4)(x+5)) ?

The solution to expand-1/(x(x+4)(x+5)) is -1/(x^3+9x^2+20x)

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expand-1/(x(x+4)(x+5))

expand

- \frac{1}{x ( x + 4 ) ( x + 5 )}

- \frac{1}{x ^{3} + 9 x ^{2} + 20 x}

Solution steps

- \frac{1}{x ( x + 4 ) ( x + 5 )}

Expand

x (x + 4) (x + 5) : x^{3} + 9 x^{2} + 20 x

= - \frac{1}{x ^{3} + 9 x ^{2} + 20 x}

\frac{( x - 2 ) ( x - 3 )}{x + 2}

\frac{1}{k ( k + 1 )} + (k + 1)

(2 - 4 i)^{7}

(x + 1) ln (3)

(Δ x + x)^{2}

What is expand-1/(x(x+4)(x+5)) ?
The solution to expand-1/(x(x+4)(x+5)) is -1/(x^3+9x^2+20x)