What is expand 4(-2/4)^3-(-2/4)^2-3(-2/4) ?

The solution to expand 4(-2/4)^3-(-2/4)^2-3(-2/4) is 3/4

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expand 4(-2/4)^3-(-2/4)^2-3(-2/4)

expand

4 (- \frac{2}{4})^{3} - (- \frac{2}{4})^{2} - 3 (- \frac{2}{4})

\frac{3}{4}

Decimal Notation

0.75

Solution steps

4 (- \frac{2}{4})^{3} - (- \frac{2}{4})^{2} - 3 (- \frac{2}{4})

Apply rule

- (- a) = a

= 4 (- \frac{2}{4})^{3} - (- \frac{2}{4})^{2} + 3 \cdot \frac{2}{4}

4 (- \frac{2}{4})^{3} = - \frac{1}{2}

= - \frac{1}{2} - (- \frac{2}{4})^{2} + 3 \cdot \frac{2}{4}

(- \frac{2}{4})^{2} = \frac{1}{2 ^{2}}

3 \cdot \frac{2}{4} = \frac{3}{2}

= - \frac{1}{2} - \frac{1}{2 ^{2}} + \frac{3}{2}

Combine the fractions

- \frac{1}{2} + \frac{3}{2} : 1

= 1 - \frac{1}{2 ^{2}}

2^{2} = 4

= 1 - \frac{1}{4}

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 1}{4}

1 \cdot 4 - 1 = 3

= \frac{3}{4}

e^{x} - e^{- x} (e^{x} - e^{- x})

- 3 (- 9 - 2)

(5 + 4 x)^{2}

\frac{( - x + 3 ) ^{3}}{3}

cosh ((x - b) (x - c))

What is expand 4(-2/4)^3-(-2/4)^2-3(-2/4) ?
The solution to expand 4(-2/4)^3-(-2/4)^2-3(-2/4) is 3/4