What is expand ((x+3)(x+1)(x-1))/((x+2)(x-4)) ?

The solution to expand ((x+3)(x+1)(x-1))/((x+2)(x-4)) is (x^3-x+3x^2-3)/(x^2-2x-8)

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expand ((x+3)(x+1)(x-1))/((x+2)(x-4))

expand

\frac{( x + 3 ) ( x + 1 ) ( x - 1 )}{( x + 2 ) ( x - 4 )}

\frac{x ^{3} - x + 3 x ^{2} - 3}{x ^{2} - 2 x - 8}

Solution steps

\frac{( x + 3 ) ( x + 1 ) ( x - 1 )}{( x + 2 ) ( x - 4 )}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{( x + 3 ) ( x + 1 ) ( x - 1 )}{x ^{2} - 2 x - 8}

Expand

(x + 3) (x + 1) (x - 1) : x^{3} - x + 3 x^{2} - 3

= \frac{x ^{3} - x + 3 x ^{2} - 3}{x ^{2} - 2 x - 8}

- \frac{2 ( y - x )}{y + 2 x} (- 1, - 2)

(\frac{x ^{2}}{12} - 6 x + 120) x

\frac{k \cdot x ^{2}}{( d - y ) ^{2}}

(x + 4 y + 1) d x + (2 x + 8 y + 4) d y

\frac{e ^{2 i z}}{z ^{4}} - \frac{z ^{4}}{( z - i ) ^{3}}

What is expand ((x+3)(x+1)(x-1))/((x+2)(x-4)) ?
The solution to expand ((x+3)(x+1)(x-1))/((x+2)(x-4)) is (x^3-x+3x^2-3)/(x^2-2x-8)