What is expand-(2(y-x))/(y+2x)(-1,-2) ?

The solution to expand-(2(y-x))/(y+2x)(-1,-2) is 1*(2(y-x))/(y+2x),2*(2(y-x))/(y+2x)

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expand-(2(y-x))/(y+2x)(-1,-2)

expand

- \frac{2 ( y - x )}{y + 2 x} (- 1, - 2)

1 \cdot \frac{2 ( y - x )}{y + 2 x}, 2 \cdot \frac{2 ( y - x )}{y + 2 x}

Solution steps

- \frac{2 ( y - x )}{y + 2 x} (- 1, - 2)

= - (- 1, - 2) \frac{2 ( y - x )}{y + 2 x}

Apply the distributive law:

a (b - c) = ab - a c

a = - \frac{2 ( y - x )}{y + 2 x}, b = - 1,, c = 2

= - \frac{2 ( y - x )}{y + 2 x} (- 1,) - (- \frac{2 ( y - x )}{y + 2 x}) \cdot 2

Apply minus-plus rules

- (- a) = a

= 1 \cdot \frac{2 ( y - x )}{y + 2 x}, 2 \cdot \frac{2 ( y - x )}{y + 2 x}

(\frac{x ^{2}}{12} - 6 x + 120) x

\frac{k \cdot x ^{2}}{( d - y ) ^{2}}

(x + 4 y + 1) d x + (2 x + 8 y + 4) d y

\frac{e ^{2 i z}}{z ^{4}} - \frac{z ^{4}}{( z - i ) ^{3}}

- \frac{1}{2} H (t - 2 π) sinh (2 (t - 2 π))

What is expand-(2(y-x))/(y+2x)(-1,-2) ?
The solution to expand-(2(y-x))/(y+2x)(-1,-2) is 1*(2(y-x))/(y+2x),2*(2(y-x))/(y+2x)