What is the first d/(dy)((M)(2x+y)) ?

The first d/(dy)((M)(2x+y)) is M

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d/(dy)((M)(2x+y))

\frac{d}{d y} ((M) (2 x + y))

M

Solution steps

\frac{d}{d y} ((M) (2 x + y))

Treat

M, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= M \frac{d}{d y} (2 x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= M (\frac{d}{d y} (2 x) + \frac{d y}{d y})

\frac{d}{d y} (2 x) = 0

\frac{d y}{d y} = 1

= M (0 + 1)

Simplify

= M

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