What is expand 3x^{1/3}(2x-1) ?

The solution to expand 3x^{1/3}(2x-1) is 6x^{4/3}-3x^{1/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3x^{1/3}(2x-1)

expand

3 x^{\frac{1}{3}} (2 x - 1)

6 x^{\frac{4}{3}} - 3 x^{\frac{1}{3}}

Solution steps

3 x^{\frac{1}{3}} (2 x - 1)

Apply the distributive law:

a (b - c) = ab - a c

3 x^{\frac{1}{3}} (2 x - 1) = 3 x^{\frac{1}{3}} \cdot 2 x - 3 x^{\frac{1}{3}} \cdot 1

= 3 x^{\frac{1}{3}} \cdot 2 x - 3 x^{\frac{1}{3}} \cdot 1

3 x^{\frac{1}{3}} \cdot 2 x = 6 x^{\frac{4}{3}}

3 x^{\frac{1}{3}} \cdot 1 = 3 x^{\frac{1}{3}}

= 6 x^{\frac{4}{3}} - 3 x^{\frac{1}{3}}

4 (\frac{1}{2} + ln (2))

(sec (θ) - tan (θ)) (sec (θ) + tan (θ))^{2}

(x^{2} + y^{2}) e^{- x^{2} - y^{2}}

x^{\frac{1}{3}} (x^{\frac{2}{3}} - x)

\frac{( 50 s )}{( s + 10 ) ( s + 1 )}

What is expand 3x^{1/3}(2x-1) ?
The solution to expand 3x^{1/3}(2x-1) is 6x^{4/3}-3x^{1/3}