What is C(s+1)(s-1)(s+1/2) ?

The solution to C(s+1)(s-1)(s+1/2) is (C(s+1)(s-1)(2s+1))/2

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simplify C(s+1)(s-1)(s+1/2)

simplify

C (s + 1) (s - 1) (s + \frac{1}{2})

\frac{C ( s + 1 ) ( s - 1 ) ( 2 s + 1 )}{2}

Solution steps

C (s + 1) (s - 1) (s + \frac{1}{2})

Simplify

s + \frac{1}{2} : \frac{2 s + 1}{2}

= C (s + 1) (s - 1) \frac{2 s + 1}{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{C ( s + 1 ) ( s - 1 ) ( 2 s + 1 )}{2}

ln (93) (- x^{2} - 55 x - 156)

(e^{2 x}) (3 e^{3 x} + 2 x)

\frac{15}{( ( 5 k - 2 ) ( 5 k + 3 ) )}

\frac{3 ( x - 1 )}{( x + 1 )}

\frac{d}{d t} ((x) (3 x + y))

What is C(s+1)(s-1)(s+1/2) ?
The solution to C(s+1)(s-1)(s+1/2) is (C(s+1)(s-1)(2s+1))/2