What is expand 3(p+4=2(p+5),p=-2) ?

The solution to expand 3(p+4=2(p+5),p=-2) is 3p+12=-6

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expand 3(p+4=2(p+5),p=-2)

expand

3 (p + 4 = 2 (p + 5), p = - 2)

3 p + 12 = - 6

Solution steps

3 (p + 4 = 2 (p + 5), p = - 2)

= 3 (p + 4 \cdot 2 =, = p (p + 5) - 2)

Distribute parentheses

3 p + 3 \cdot 4 = 2 (p + 5), p = 3 (- 2)

Apply minus-plus rules

+ (- a) = - a

3 p + 3 \cdot 4 = 2 (p + 5), p = - 3 \cdot 2

Simplify

3 p + 3 \cdot 4 = 2 (p + 5), p = - 3 \cdot 2 : 3 p + 12 = - 6

3 p + 12 = - 6

\frac{ab - b ^{2} - a c - b c}{( b - c ) ( a ^{2} - b ^{2} )}

\frac{n ( n + 1 ) ( 2 n + 1 ) ( 3 n ^{2} + 3 n - 1 )}{30}

\frac{\partial}{\partial x} ((z) (ln (3 x yz) - z))

(x - \frac{y}{y ^{'} ( x )})^{2} + (y - x y^{'} (x))^{2}

\frac{3 ( 3 + h )}{4 ( h + 4 ) ^{2}}

What is expand 3(p+4=2(p+5),p=-2) ?
The solution to expand 3(p+4=2(p+5),p=-2) is 3p+12=-6