What is expand-((2^3)/3)-((2^2)/2)+12 ?

The solution to expand-((2^3)/3)-((2^2)/2)+12 is 22/3

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expand-((2^3)/3)-((2^2)/2)+12

expand

- (\frac{2 ^{3}}{3}) - (\frac{2 ^{2}}{2}) + 12

\frac{22}{3}

Decimal Notation

7.33333 \dots

Solution steps

- (\frac{2 ^{3}}{3}) - (\frac{2 ^{2}}{2}) + 12

Remove parentheses:

(a) = a

= - \frac{2 ^{3}}{3} - \frac{2 ^{2}}{2} + 12

Cancel

\frac{2 ^{2}}{2} : 2

= - \frac{2 ^{3}}{3} - 2 + 12

Add/Subtract the numbers:

- 2 + 12 = 10

= - \frac{2 ^{3}}{3} + 10

2^{3} = 8

= - \frac{8}{3} + 10

Convert element to fraction:

10 = \frac{10 \cdot 3}{3}

= \frac{10 \cdot 3}{3} - \frac{8}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{10 \cdot 3 - 8}{3}

10 \cdot 3 - 8 = 22

= \frac{22}{3}

P (1, - 2) y Q (3, 4)

\frac{( 3 - 5 + x ) ( 2 + 8 - x )}{x - 4}

2 (a + 2 e)

\frac{x}{( x + 3 ) ( x - 2 )}

3 (3 + 6)

What is expand-((2^3)/3)-((2^2)/2)+12 ?
The solution to expand-((2^3)/3)-((2^2)/2)+12 is 22/3