What is expand (1+t)y''(t)+(-1+t)y'(t)-2y ?

The solution to expand (1+t)y''(t)+(-1+t)y'(t)-2y is y''(t)+ty''(t)-y'(t)+ty'(t)-2y

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expand (1+t)y''(t)+(-1+t)y'(t)-2y

expand

(1 + t) y^{''} (t) + (- 1 + t) y^{'} (t) - 2 y

y'' (t) + t y'' (t) - y' (t) + t y' (t) - 2 y

Solution steps

(1 + t) y^{''} (t) + (- 1 + t) y^{'} (t) - 2 y

Expand

y^{''} (t) (1 + t) : y^{''} (t) + t y^{''} (t)

= y^{''} (t) + t y^{''} (t) + (- 1 + t) y^{'} (t) - 2 y

Expand

y^{'} (t) (- 1 + t) : - y^{'} (t) + t y^{'} (t)

= y^{''} (t) + t y^{''} (t) - y^{'} (t) + t y^{'} (t) - 2 y

(f \circ g) (2 x + 1) - 3

d x d (x^{6} + 3 x^{4} + 7 x^{2})

\frac{s}{( s ^{2} + n ^{2} ) ( s - 4 )}

, \frac{3}{4} (v - 16)

(2 x - 3 y) (4 x - 5 y)

What is expand (1+t)y''(t)+(-1+t)y'(t)-2y ?
The solution to expand (1+t)y''(t)+(-1+t)y'(t)-2y is y''(t)+ty''(t)-y'(t)+ty'(t)-2y