What is K(1+A+(-A-2B)/z+B+B/(z^2)) ?

The solution to K(1+A+(-A-2B)/z+B+B/(z^2)) is (K(z^2+Az^2-Az-2Bz+B+Bz^2))/(z^2)

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simplify K(1+A+(-A-2B)/z+B+B/(z^2))

simplify

K (1 + A + \frac{- A - 2 B}{z} + B + \frac{B}{z ^{2}})

\frac{K ( z ^{2} + A z ^{2} - A z - 2 B z + B + B z ^{2} )}{z ^{2}}

Solution steps

K (1 + A + \frac{- A - 2 B}{z} + B + \frac{B}{z ^{2}})

Join

1 + A + \frac{- A - 2 B}{z} + B + \frac{B}{z ^{2}} : \frac{z ^{2} + A z ^{2} - A z - 2 B z + B + B z ^{2}}{z ^{2}}

= K \frac{z ^{2} + A z ^{2} - A z - 2 B z + B + B z ^{2}}{z ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{K ( z ^{2} + A z ^{2} - A z - 2 B z + B + B z ^{2} )}{z ^{2}}

(cos (3 θ) + i sin (3 θ))^{3}

(2 + i)^{18}

- 3 (5 - 4 csc (θ) = csc (θ))

v a l u e (g - f) (3)

lo g_{10} (10000 t)

What is K(1+A+(-A-2B)/z+B+B/(z^2)) ?
The solution to K(1+A+(-A-2B)/z+B+B/(z^2)) is (K(z^2+Az^2-Az-2Bz+B+Bz^2))/(z^2)