What is expand cos(2θ)+tan(θ)(sin(2θ)+tan(θ)) ?

The solution to expand cos(2θ)+tan(θ)(sin(2θ)+tan(θ)) is cos(2θ)+sin(2θ)tan(θ)+tan^2(θ)

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expand cos(2θ)+tan(θ)(sin(2θ)+tan(θ))

expand

cos (2 θ) + tan (θ) (sin (2 θ) + tan (θ))

cos (2 θ) + sin (2 θ) tan (θ) + tan^{2} (θ)

Solution steps

cos (2 θ) + tan (θ) (sin (2 θ) + tan (θ))

Apply the distributive law:

a (b + c) = ab + a c

tan (θ) (sin (2 θ) + tan (θ)) = tan (θ) sin (2 θ) + tan (θ) tan (θ)

= cos (2 θ) + tan (θ) sin (2 θ) + tan (θ) tan (θ)

Simplify

tan (θ) sin (2 θ) + tan (θ) tan (θ) : sin (2 θ) tan (θ) + tan^{2} (θ)

= cos (2 θ) + sin (2 θ) tan (θ) + tan^{2} (θ)

\frac{5 ( 2 x - 1 ) ( 2 x + 1 )}{( x - 5 ) ( x + 5 )}

x^{4} (x^{5} - 10)^{12} d x

7 (\frac{2}{13} x + \frac{3}{13} y)^{2}

\frac{1}{s ^{2} ( s + 1 ) ^{2}}

(1 + ln (x)) (- e + 2 x - x ln (x))

What is expand cos(2θ)+tan(θ)(sin(2θ)+tan(θ)) ?
The solution to expand cos(2θ)+tan(θ)(sin(2θ)+tan(θ)) is cos(2θ)+sin(2θ)tan(θ)+tan^2(θ)